匯文網(wǎng) > 辦公-PPT-報(bào)告 > 文案-方案 > C語言程序設(shè)計(jì)第三版譚浩強(qiáng)課后習(xí)題答案完整版(完整版).doc

C語言程序設(shè)計(jì)第三版譚浩強(qiáng)課后習(xí)題答案完整版(完整版).doc

C語言程序設(shè)計(jì)第三版譚浩強(qiáng)課后習(xí)題答案完整版（完整版）(文檔可以直接使用，也可根據(jù)實(shí)際需要修改使用,可編輯歡迎下載） .5C * Very Good! * mian() printf(*); printf(n); printf(Very Good!n); printf(n); printf(*); .6 abc mian() int a,b,c,max; printf(a,b,c:n); scanf(%d,%d,%d,&a,&b,&c); max=a; if(maxb) max=b; if(maxc) max=c; printf(%d,max); 3.6 main() char c=a,c=b,c3=c,c4=0,c5=6; printf(a%cb%ctc%ctabcn,c,c,c3); printf(tb%c %c,c4,c5); aabbccabc AN 3.7China4A4EEAChinaGlmreclcc3c4c5Chinaccc3c4c5Glmre #include main() char c=C,c=h,c3=i,c4=n,c5=a; c+=4; c+=4; c3+=4; c4+=4; c5+=4; printf(%c%c%c%c%cn,c,c,c3,c4,c5); Glmre 3.9 x+a%3*(int)(x+y)%/4 x=.5,a=7,y=4.7 (float)(a+b)/+(int)x%(int)y a=,b=3,x=3.5,y=.5 .5 3.5 3.0 main() int i,j,m,n; i=8; j=0; m=+i; n=j+; printf(%d,%d,%d,%d,i,j,m,n); 990 3. aa=an a+=a a-= 3 a*=+3 4a/=a+a 5 a%=(n%=)n5 6a+=a-=a*=a () 4 () 0 (3) 60 (4) 0 (5) 0 (6) 0 44a=3b=4c=5x=.y=.4z=-3.6u=574n=8765c=ac=b a=_3_ _b=_4_ _c=_5 x=.00000,y=.400000,z=-3.600000 x+y=_3.600_ _y+z=-.0_ _z+x=-.40 c=a_or_97(ASCII) c=b_or_98(ASCII) main() int a=3,b=4,c=5; long int u=574,n=8765; float x=.,y=.4,z=3.6; char c=a,c=b; printf(a=%d b=%d c=%dn,a,b,c); printf(x=%f,y=%f,z=%fn,x,y,z); printf(x+y=%5.f y+z=%5.f z+x=%5.fn,x+y,y+z,z+x); printf(u=%6ld n=%9ldn,u,n); printf(%s %s %d%sn,c=a,or,c,(ASCII); printf(%s %s %d%sn,c=a,or,c,(ASCII); 47scanfa=3b=7x=8.5y=7.8c=Ac=a main() int abfloat xychar cc scanfa=%d_b=%d&a&b scanf_x=%f_y=%e,&x&y scanf_c=%c_c=%c&c&c a=3_b=7 _x=8.5_y=7.8 _c=A_c=a 48r=.5h=3scanf main() float r,h,C,Sa,Sb,Va,Vb; scanf(%f,%f,&r,&h); C=*3.4*r; Sa=3.4*r*r; Sb=4*Sa; Va=4*3.4*r*r*r/3; Vb=Sa*h; printf(C=%.fn,C); printf(Sa=%.fnSb=%.fnVa=%.fnVb=%.fn,Sa,Sb,Va,Vb); 49 c=5(F-3)/9 main() float F,c; scanf(%f,&F); c=5*(F-3)/9; printf(c=%.f,c); 40getcharccccccASCIIputcharprintf charcc intcc #includestdio.h main() char c,c; c=getchar();c=getchar(); putchar(c);putchar(n);putchar(c);putchar(n); #includestdio.h main() char c,c; c=getchar();c=getchar(); printf(c=%d c=%dn,c,c); printf(c=%c c=%cn,c,c); 5. 5. C 0003&53&5 5.3 a=3b=4c=5 () a+bc&b=c () a|b+c&b-c (3) !(ab)&!c| (4) !(x=a)&(y=b)&0 (5) !(a+b)+c-&b+c/ () 0 () (3)

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關(guān) 鍵詞：: 語言程序設(shè)計(jì) 第三版譚浩強(qiáng) 課后習(xí)題答案完整版

資源描述：: C語言程序設(shè)計(jì)第三版譚浩強(qiáng)課后習(xí)題答案完整版（完整版） (文檔可以直接使用，也可根據(jù)實(shí)際需要修改使用,可編輯歡迎下載）￡±.5??2???±???àyìa￡?±àD′￡-??C3ìDò￡?ê?3?ò???D??￠￡o ************************** Very Good! ************************** ?a￡o mian() {printf("**************************"); printf("\n"); printf("Very Good!\n"); printf("\n"); printf("**************************"); } ￡±.6 ±àD′￡-??3ìDò￡?ê?è?a?￠b?￠cèy???μ￡?ê?3????D×?′ó?μ?￡ ?a￡o mian() {int a,b,c,max; printf("??ê?è?èy??êya,b,c:\n"); scanf("%d,%d,%d",&a,&b,&c); max=a; if(max main() { char c￡±='C',c￡2='h',c3='i',c4='n',c5='a'; c￡±+=4; c￡2+=4; c3+=4; c4+=4; c5+=4; printf("?ü??ê?%c%c%c%c%c\n",c￡±,c￡2,c3,c4,c5); } ??DD?á1?￡o ?ü??ê?Glmre 3.9?ó??????ê?±í′?ê?μ??μ?￡￡¨￡±￡?x+a%3*(int)(x+y)%￡2/4 éèx=￡2.5,a=7,y=4.7 ￡¨￡2￡?(float)(a+b)/￡2+(int)x%(int)y éèa=￡2,b=3,x=3.5,y=￡2.5 ￡¨￡±￡?￡2.5 ￡¨￡2￡?3.5 3.￡±0D′3?3ìDò??DDμ??á1??￡ main() {int i,j,m,n; i=8; j=￡±0; m=++i; n=j++; printf("%d,%d,%d,%d",i,j,m,n); } ?a￡o 9￡?￡±￡±￡?9￡?￡±0 3.￡±￡2 D′3?????±í′?ê?????oóa(chǎn)μ??μ￡?éè?-à′a=￡±￡2?￡éèaoín??ò??¨ò??a??Dí±?á??￡￡¨￡±￡?a+=a ￡¨￡2￡? a-=￡2 ￡¨3￡? a*=￡2+3 ￡¨4￡?a/=a+a ￡¨5￡? a%=(n%=￡2)￡?nμ??μμèóú5 ￡¨6￡?a+=a-=a*=a ?a￡o (￡±) ￡24 (￡2) ￡±0 (3) 60 (4) 0 (5) 0 (6) 0 μú???? 4￡?4è?a=3￡?b=4￡?c=5￡?x=￡±.￡2￡?y=￡2.4￡?z=-3.6￡?u=5￡±￡274￡?n=￡±￡28765￡?c￡±='a'￡?c￡2='b'?￡??μ?μ?ò???ê?3???ê?oí?á1?￡???D′3?3ìDò￡¨°üà¨?¨ò?±?á?ààDíoíéè??ê?3?￡??￡ a=_3_ _b=_4_ _c=_5 x=￡±.￡200000,y=￡2.400000,z=-3.600000 x+y=_3.600_ _y+z=-￡±.￡20_ _z+x=-￡2.40 c￡±=¨@a¨@_or_97(ASCII) c￡2=¨@b¨@_or_98(ASCII) main() {int a=3,b=4,c=5; long int u=5￡±￡274,n=￡±￡28765; float x=￡±.￡2,y=￡2.4,z=3.6; char c￡±='a',c￡2='b'; printf("a=%￡2d b=%￡2d c=%￡2d\n",a,b,c); printf("x=%f,y=%f,z=%f\n",x,y,z); printf("x+y=%5.￡2f y+z=%5.￡2f z+x=%5.￡2f\n",x+y,y+z,z+x); printf("u=%6ld n=%9ld\n",u,n); printf("%s %s %d%s\n","c￡±='a'","or",c￡±,"(ASCII)"); printf("%s %s %d%s\n","c￡2='a'","or",c￡2,"(ASCII)"); } 4￡?7ó?scanf????μ?oˉêyê?è?êy?Y￡?ê1a=3￡?b=7￡?x=8.5￡?y=7￡±.8￡2￡?c￡±=¨@A¨@￡?c￡2=¨@a¨@￡??ê?ú?ü?ìé?è?o?ê?è?￡? main() { int a￡?b￡?float x￡?y￡?char c￡±c￡2￡? scanf￡¨"a=%d_b=%d"￡?&a￡?&b￡?￡? scanf￡¨"_x=%f_y=%e",&x￡?&y￡?￡? scanf￡¨"_c￡±=%c_c￡2=%c"￡?&c￡±￡?&c￡2￡?￡? } a=3_b=7 _x=8.5_y=7￡±.8￡2 _c￡±=A_c￡2=a 4￡?8éè?2°???r=￡±.5￡??2?ù??h=3￡??ó?2?ü3¤?￠?2???y?￠?2?ò±í???y?￠?2?òì??y?￠?2?ùì??y?￡ó?scanfê?è?êy?Y￡?ê?3??????á1?￡?ê?3?ê±òa?ó??×??μ?÷￡?è?D?êyμ?oóá???êy×??￡??±à3ìDò?￡ main() {float r,h,C￡±,Sa,Sb,Va,Vb; scanf("%f,%f",&r,&h); C￡±=￡2*3.￡±4*r; Sa=3.￡±4*r*r; Sb=4*Sa; Va=4*3.￡±4*r*r*r/3; Vb=Sa*h; printf("C￡±=%.￡2f\n",C￡±); printf("Sa=%.￡2f\nSb=%.￡2f\nVa=%.￡2f\nVb=%.￡2f\n",Sa,Sb,Va,Vb); } 4￡?9ê?è?￡-???aê????è￡?òa?óê?3?é?ê????è?￡1?ê??a c=5(F-3￡2)/9 ê?3?òa?óóD??×??μ?÷￡?è???￡2D?êy?￡ main() {float F,c; scanf("%f",&F); c=5*(F-3￡2)/9; printf("c=%.￡2f",c); } 4￡?￡±0±à3ìDò￡?ó?getcharoˉêy?áè?á???×?·???c￡±?￠c￡2￡?è?oó·?±eó?oˉêyoíoˉêyê?3??aá???×?·??￡2￠????ò????êìa￡o￡¨￡±￡?±?á?c￡±?￠c￡2ó|?¨ò??a×?·?Dí?ò??D?￡?ò??t?????é￡?￡¨￡2￡?òa?óê?3?c￡±oíc￡2?μμ?ASCII??￡?ó|è?o?′|àí￡?ó?putcharoˉêy?1ê?printfoˉêy￡?￡¨￡3￡???D?±?á?ó?×?·?±?á?ê?·??úè?o??é???????éò??￥?à′úì?￡?è?￡o char??c￡±￡?c￡2￡? ó? int??c￡±￡?c￡2￡? ê?·??Tì??tμ?μè??￡? #include"stdio.h" main() {char c￡±,c￡2; c￡±=getchar();c￡2=getchar(); putchar(c￡±);putchar('\n');putchar(c￡2);putchar('\n'); } #include"stdio.h" main() {char c￡±,c￡2; c￡±=getchar();c￡2=getchar(); printf("c￡±=%d c￡2=%d\n",c￡±,c￡2); printf("c￡±=%c c￡2=%c\n",c￡±,c￡2); } μú???? 5.￡± ê2?′ê???ê?????￡?ê2?′ê?1??μ????￡?ê2?′ê????-????￡? ?a￡o???￡ 5.￡2 Có????Dè?o?±íê?"??"oí"?ù"￡??μí3è?o??D??￡-??á?μ?"??"oí"?ù"￡? ?a￡oéèóD￡-?????-±í′?ê?￡?è????á1??a"??"￡??òò?￡±±íê?￡?è????á1??a"?ù"￡??òò?0±íê??￡μ?ê??D??￡-?????-á?μ??μê±￡?ò?0′ú±í"??"￡?ò?·?0′ú±í"?ù"?￡àyè?3&&5μ??μ?a"??"￡??μí3??3?3&&5μ??μ?a￡±?￡ 5.3 D′3??????÷???-±í′?ê?μ??μ?￡éèa=3￡?b=4￡?c=5?￡ (￡±) a+b>c&&b==c (￡2) a||b+c&&b-c (3) !(a>b)&&!c||￡± (4) !(x=a)&&(y=b)&&0 (5) !(a+b)+c-￡±&&b+c/￡2 ?a￡o (￡±) 0 (￡2) ￡± (3) ￡±

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