有機(jī)波譜分析雙語(yǔ)課程 (24).pdf
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1、P1:Hello everyone,welcome to Organic Spectroscopic Analysis.In the last lecture,I have introduced you 13C NMR spectroscopy.This lecture,we are going to learn more about it.P1:大家好,歡迎來(lái)到有機(jī)波譜分析課程。在上一講中,我向大家介紹了13C NMR 光譜,這一節(jié)課我們將了解更多13C NMR。P2:In 13C NMR,chemical shifts are in the range of 0-230 ppm,much
2、wider window than 1H NMR.The 13C NMR signal for TMS is again the standard.Similar to 1H NMR,there are same kinds of factors influence chemical shifts.P2:在13C NMR 中,化學(xué)位移在 0-230 ppm 的范圍內(nèi),比 1H NMR 的范圍寬得多。TMS 也是13 C NMR 的內(nèi)標(biāo)。與1H NMR 具有相似的影響化學(xué)位移的因素。P3:13 C NMR spectrum gives you:1.Number of Different Carb
3、on atoms 不同碳原子的數(shù)目 2.Chemical Type of Carbons 碳的化學(xué)類(lèi)型 13 C NMR has Wide chemical shift range.The common chemical shift range of 1H NMR is 0-10ppm,and the common range of 13C NMR is 0-120,which is about 20 times of 1H NMR.This greatly eliminates the overlapping of carbon atoms in different chemical env
4、ironments and greatly improves the resolution.P3:13 C NMR 光譜給出:1.不同碳原子數(shù)目 2.碳的化學(xué)類(lèi)型 13 C NMR 具有寬的化學(xué)位移范圍。1H NMR 的常見(jiàn)化學(xué)位移范圍為0-10,而13C NMR 的常見(jiàn)范圍為0-120,約為1H NMR 的 20 倍。這極大地消除了不同化學(xué)環(huán)境中碳原子峰的重疊,并大大提高了分辨率。(2)13 C NMR has large coupling constant Due to the low natural abundance of 13C,and the probability of the
5、carbon atom directly connected to C is very small,so 13C-13C coupling is generally not considered in Carbon NMR spectrum.Carbon atoms are often connected to hydrogen atoms,and they can be coupled to each other.13C-1H coupling constant value is very large,generally in 125-250 Hz.This coupling does no
6、t affect the 1H NMR spectrum,but it is dominant in the carbon spectrum.(2)由于13C 天然豐度低,與它直接相連的碳原子也是 13C 的幾率很小,故在碳譜中一般不考慮 13C-13C 偶合,而碳原子常與氫原子連接,它們可以相互偶合,這種 13C-1H 偶合常數(shù)的數(shù)值很大,一般在 125-250 Hz。這種偶合并不影響 1H NMR 譜,但在碳譜中是主要的。But usually,13C NMR is not quantitative.Because the peak intensity is not proportiona
7、l to the number of carbon atoms Only when the system is in equilibrium,that is,it forms to the Boltzmann distribution,and the intensity of the spectral peak is proportional to the number of resonance nuclei of the peak.Due to the long relaxation time of the 13C nucleus,the resonance peak is usually
8、observed in a non-equilibrium state,and the relaxation time of carbon atoms on different groups is different.So the intensity of the 13C NMR spectrum peak is often not the same as the carbon nucleus that produced the peak.通常,13C NMR 不定量,因?yàn)樽V峰強(qiáng)度不與碳原子數(shù)成正比。體系只有處在平衡狀態(tài),即符合波爾茲曼分布時(shí),譜峰強(qiáng)度才與該峰共振核數(shù)目成正比。由于13C 核
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